**Chapter 1 Grade 7 Integer Review**

(+4) + (-2) = +2

Positive (4) and Negative (2) = positive 2

have 4 and owe 2 = have 2

Standard Form:

4 - 2 = -2

Make zero pairs:

-16 = +16, -5 = + 5, +6 = -6, -2 = +2, -10 = +10,+3 = -3,+1

1 = -11, -9 = +9

**Chapter 2**

Multiplying Integers

(-2) x (+3)

(+3) x (-2) = -6

remove 2 groups of (+3) --> use zero pairs remove and...

(+2) x (+3) = +6

2 groups of (+3) = +6

(-2) x (-3) = +6

(2) x (+3) = -6

2 groups of (-3) = -6

Sign Rule (negative signs)

Even - When you have an even number of NEGATIVE factors the product is POSITIVE.

ODD - When you have an odd number of NEGATIVE factors the product is NEGATIVE.

Partitive Division:

ODD - When you have an odd number of NEGATIVE factors the product

Chapter 3 Division IntegersChapter 3 Division Integers

**Chapter 4: Order of Operations with Integers**

How I would solve this problem is first follow BEDMAS I would first put brackets on (-6) ÷ (-3) so it would look like this [(6) ÷ (-3)] and you would get an answer of -2 then I solved (+5) x (-3) = -15 So then I added -15 + -2 = -17

## No comments:

## Post a Comment