Kathryn's Homework 3,7,11

3)



ANSWER:
a) 420 m. I added the length and width .

b) a²+ b²=c²
300²+120²=c²
(300X300)+(120X120)=c²
90000m²+14400m²=c²
104400m²=c²
√104400m²=c
323.10m=c


c) 420m-323.10= 97.10 m
Maria walked farther by 97.10 meters.


7)

ANSWER :

a²=c²-b²
a²=80²-79²
a²=(80X80)-(79X79)
a²=6400cm²-6241cm²
a²=159cm²
a=√159cm²
a=12.61cm


11)

The maximum length of the ladder is 291.71cm and the minimum length is 291.10.

LINKS:

INFORMATION
EXERCISES

VIDEO:

PLEASE LET ME KNOW IF MISTAKES WERE MADE. THANK YOU:))

AJ's Scribe Post

Questions 3,9,14.

3.

A)420m

120m+300m = 420m

B)323m

a²+b²=c²

120m²+300m²=c²

(120x120)+(300x300)=c²

104400m²= c²

√104400m²= c²

√323²= √c²

C) Maria walked further by 97m

9.

A)4.2cm

B)34cm

14.

15.6mm

Cameron's Homework Book Post: pg. 33 Numbers 6,7,8

I have chosen to do questions 6, 7, and 8 in the homework book on page 33.

6. The width of a rectangle is 8cm, and its diagonal is 17cm.

a) Calculate the length of the rectangle. Show your work!
c² - b² = a²
17² - 8² = a²
(17x17) - (8x8) = a²
289cm² - 64cm² = 225cm²
225cm² = c²
√225cm² = √c²
15cm² = c²


7. A quadrilateral has a width of 17cm and a length of 26cm. A diagonal is 31cm. Is the quadrilateral a rectangle? Justify your answer.

a² + b² = c²
26² + 17² = c²
(26x26) + (17x17) = c²
676cm² + 289cm² = 965cm²
965cm² = c²
√965cm² = √c²
31.06cm²

Answer: No, the corners do not meet at right angles because 17² + 26² ≠ 31²


8. A ship leaves port heading due west. After travelling at a speed of 20 km/h for 10h, the ship makes a 90 degree turn and heads south, travelling south for 7.5 h, how far is the ship from the port? Show your work.

20 km/h for 10h west equals 200km
20 km/h for 7.5h south equals 150km
200 km² + 150km²=?
40,000km + 22,500km = 62500km
✓62,500km = 250km²

Answer: The ship is 250km² away from the port.

Here is a video:




Heres a link:
http://www.mathsisfun.com/pythagoras.html

Heres a game to help you:
http://www.kidsnumbers.com/pythagorean-theorem-game.php

I'm sorry that their aren't any pictures, my computer won't let me put them on.

Hope this helps!

Pythagoras Textbook Number 15

#15 The coordinate grid shown was drawn on centimetre grid paper. What is the length of line segment AB? Express your answer to the nearest tenth of a centimetre.

















Answer:

















I got 2 cm for side a and i got 4 cm for side b because i counted the units AB were taking up on the graph paper vertically and horizontally.




PS:

I know i wasn't assigned this scribe but Thessa didn't have the answer so I just wanted share what i got if people were curious about the answer.. I'm not exactly sure if I'm right but there you go (: sorry harbeck !

Link: http://www.mathsisfun.com/pythagoras.html


Video:

Pythagoras Textbook Questions and Answers

5, 8, 11, and 14!

QUESTION #5:

a) What is the area of each square attached to the legs of the right triangle?

b) What is the area of the square attached to the hypotenuse?

c) What is the length of the hypotenuse?

ANSWER:
a.) 6 x 6 = 36

8 x 8 = 64

b.)a² + b² = c²

6² + 8² = c²

( 6 x 6 ) + ( 8 x 8 ) = c x c

36 cm² + 64 cm² = c²

100 cm² = c²

The area of the square is 100 cm.

c.) √c² = √100 cm²

c = 10 cm

The length of the hypotenuse is 10 cm.

QUESTION #8:

The side view of a

ramp at a grocery

store is in the shape of

a right triangle. Determine the length

of the ramp, to the nearest centimetre.

ANSWER:

a² + b² = c²

50² + 200² = c²

( 50 x 50 ) + ( 200 + 200 ) = c x c

2500 cm² + 40 000 cm² = 42500 cm²

√42500 cm² = 206 cmQUESTION # 11:

The right triangle below has a square

attached to its hypotenuse. What is the

perimeter

of the triangle? Give your

answer to the nearest tenth of a centimetre.

ANSWER:

√914 = 30.2

a² + b² = c²

17² + b² = 30.2²

b² = 30.2 ² - 17²

b² = ( 30.2 x 30.2 ) - ( 17 x 17 )

b² = 912.04 cm² - 289 cm²

b² = 623.04

√b² = √623.04

b = 24.9

The perimeter is 72.1 m.

QUESTION #14:

What are the lengths of b and c? Write your answer to the nearest tenth of a metre where

appropriate.

ANSWER:

FIRST TRIANGLE:

a² + b² = c²

3² + b² = 5²

b² = 5² - 3²

b² = ( 5 x 5 ) - ( 3 x 3 )

b² = 25 m² - 9 m²

b² = 16 m²

√b² = √16m²

b = 4 m

SECOND TRIANGLE:

a² + b² = c²

6² + 4² = c²

( 6 x 6 ) + ( 4 x 4 ) = c x c

36 m² + 16 m² = 52 m²

√c² = √52 m²

c = 7.2

HERE'S A VIDEO FOR YOU TO WATCH :)

HERE ARE SOME LINKS:

http://library.thinkquest.org/20991/geo/stri.html

http://mathforum.org/~sarah/hamilton/ham.legs.html

http://www.mathguide.com/lessons/Pythagoras.html

HOMEWORKS:

MATH TEXTBOOK. pg 104 - 105

MATH HOMEWORK BOOK pg. 30 - 31

IF I MADE A MISTAKE, PLEASE COMMENT BELOW AND CORRECT ME :)

Home Work Booklet

P.30-31
#2,4,6,8

2.
A)C=35m2
B)C=42m2

4.
A)V=12cm2
B)Z=12cm2

6.
The height of the triangle is 10.2cm2

8.I think that the triangle is not a right triangle, because the legs don't equal the hypotenuse.

a2+b2=c2
2m2+3m2=52
(2x2)+(3x3)=(5x5)
4m2+9m2=13m2
13m2 does not equal 25m2

Correct me if i am wrong on anything.

Justin Lorenzo's Math homework book Scribe Post

Our homework : math textbook pages 104 & 105, math homework book pages 30 - 31.

Math homework book pages 30 - 31 (odd numbers)

1.) Pythagorean, Length, Hypotenuse, Legs

3.)
a.) it is 41 cm
b.) it is 37 m

5.)
a.) it is 3.3 cm
b.)it is 9.7 cm

7.)
a.) it is 4.5 m
b.) it is 17 m

Tell me what you think!
Do you agree?Or disagree?

Pythagoras Scribe Post 5

I did numbers 6,9,12 and 15.

6.
a)
I subtract c² and a² so that i can b².
b)

I first squared the two numbers then subtract them. After that I find the square root of the difference then I got 10cm.

9.Tianna wants to construct a path along the diagonal of her yard.What length will the path be?Express your answer to the nearest tenth of a metre.

12.The hypotenuse of the triangle cuts the circle in half.What is the diameter of the circle? express your answer to the nearest tenth of a centimetre.

15.The coordinate grid shown was drawn on a centimetre grid paper. What is the length of the line segment AB. Express your answer to the nearest tenth of a centimetre.

the square root of 6.32.

Here are some links.

http://www.historyforkids.org/learn/greeks/science/math/pythagoras.htm

http://www.mathsisfun.com/pythagoras.html

Here is a video to help.


I'm not sure about my answer in no.15 but I think i'm wrong.
Leave comments and suggestions

Aj's Pythagoras scribe

4.

30x30 = 900mm2

40x40=1600mm2

50x50=2500mm2

9.

a)

2x2 = 4cm2

3x3 = 9cm2

4x4 = 16cm2

b) It isn't a right triangle because the legs do not equal the hypotenuse.

12.

a)52cm2

b)676mm2

c)65cm2

d)24cm2

17.

a)1225cm2

b)169mm2

Links :

http://www.historyforkids.org/learn/greeks/science/math/pythagoras.htm

http://www.cut-the-knot.org/pythagoras/

Video:

Daniel's Pythagoras Scribe Post

Hope you all did your homework ! The pages were 91 - 94 . If you were stuck on any of of the following numbers ( 2, 7, 14, & 18. ) i hope this helped you .



2) A triangle has side lengths of 7cm, 11cm, & 15cm. Explain how you can determine whether or not it is a right triangle.

In order for a right triangle to be a right triangle , a2 + b2 = c2 . In this question a2 + b2 does not equal c2 . Therefore this triangle is not a right triangle.

7) The sides of a right triangle measure 9cm, 12cm, & 15cm.

a) What is the area of each square attached to the three sides of the right triangle?

a2=144cm

b2=81cm

c2=225cm

b) Write an addition statement showing the relationship between the areas of the three squares.
c) Describe, using words and symbols, the relationship between the side lengths of each square.


- The area of square a2 + square b2 is equvilent to square c2.

14) Show whether each triangle in the table is a right triangle.

18)The diagram is made of two triangles and five squares.

The area of square x is 28cm²

b) What is the area of square Y?

The area of square Y is 16cm2 because the hypotenuse for the 2 triangles is 28cm², and side B is 12cm2, therefore 16cm2+12cm2 = 28cm2. I think the question is asking ___ + 12cm2 = 28cm2





Links : Pythagorean Theorem ( this is the video )

Thank you Marilen for helping me finish this . Hope you all liked it (:

Angel's Pythagoras Scribe Post

Scribe 3: Pg 91-93 #3, 8, 11, 16

3. For the triangle shown, Kenda wrote the Pythagorean relationship as r2 = p2 + q2. Is she correct? Explain.














She's not correct because the right formula would be q2 + r2 = p2 because the longest line is labeled p2 which is opposite from the right angle which makes it the hypoteneuse.










8. Is the triangle shown a right triangle? Explain your reasoning.



















No, because in this case a + b doesn't equal to 50. a + b = 60







11. The side lenghts of a triangle are 5cm, 6cm, and 8cm. Determine whether the triangle is a right triangle. Explain.








16. Baldeep is building a wooden box for storing colored pencils. The box will have rectangular sides that are 12 cm wide and 20 cm long. Show how Baldeep can be sure the sides are rectangular, without using a protractor.














Links: www.mathsisfun.com/pythagoras.html
http://www.historyforkids.org/learn/greeks/science/math/pythagoras.htm

Video:



URL of textbook pictures:
http://ebook.mytextbook.ca/view.phpp=eef24f6cac95bfcf8e97648bbda1b669190f187a&c=2

Homework for weekend: Pages 91-94 #1-21

Diana's Pythagoras Scribe Post

Homework for the weekend : Pages 91-94 #1-21

My homework was questions : 3, 8, 11, & 16




3. Kendra wrote the Phythagorean relationship as r2= p2 + q2. Is she correct ? Explain.


Kendra is incorrect. Leg2 + leg2 = hypotenuse2. Since the legs are r and q and the hypotenuse is p, It should be r2+q2=p2 or q2+r2=p2.




8. Is the triangle shown a right triangle ? Explain your answer.


The triangle is not a right triangle. For this triangle to be a right triangle, the area of the two smaller squares must equal the area of the larger one. Because a + b = 60 not 50.




11. The side lengths of a triangle are 5 cm, 6cm, and 8cm. Determine whether the triangle is a right triangle. explain.

It is not a right triangle since the sum of the areas of the two smaller squares aren't equal to the larger square. (6x6)= 36cm2 , (5x5)= 25cm2, 36+25=61. 61 doesn't equal 64.




16. Baldeep is building a wooden box for storing coloured pencils. The box will have rectangular sides that are 12 cm wide and 20 cm long. Show how Baldeep can be sure the sides are rectangular, without using a protractor.

A2 + B2 = C2 ,
(12x12)+(20x20)= C2,
144cm2 +400cm2= C2,
544cm2= C2.
The box with be 544cm2.


Video:



Tell me if I did anything wrong. Also make sure to have all your work done for monday.

Marilen's Pythagoras Scribe Post

Homework for the weekend : Pages 91-94 #1-21
My homework was questions 2, 7, 14, & 18.

2) A triangle has side lengths of 7cm, 11cm, & 15cm. Explain how you can determine whether or not it is a right triangle.


In order for a triangle to be a right triangle, a²+b²=c². In this case, a²+b² does NOT equal c² therefore, this is NOT a right triangle.

7) The sides of a right triangle measure 9cm, 12cm, & 15cm.


a) What is the area of each square attached to the three sides of the right triangle?

area for a²= 144cm²
area for b²= 81cm²
area for c²= 225cm²

b) Write an addition statement showing the relationship between the areas of the three squares.

c) Describe, using words and symbols, the relationship between the side lengths of each square.
-The area sum of the squares a & b equals the area of square c.

14) Show whether each triangle in the table is a right triangle.

18)The diagram is made of two triangles and five squares.

a) What is the area of square X?

The area of square X is 28cm²

b) What is the area of square Y?
The area of square Y is 16cm² because the hypotenuse for the 2 triangles is 28cm², and side B is 12cm², therefore 16cm²+12cm² = 28cm². The question was basically asking, ' what + 12cm² = 28cm²? ', in my point of view.

Links:
Pythagorean Theorem
Pythagoras Theorem

Videos: