Showing posts with label Kathryn8-17. Show all posts
Showing posts with label Kathryn8-17. Show all posts

Sunday, May 8, 2011

Kathryn's Algebra Post

ALGEBRA- a part of mathematics that uses mathematical statements using letters to represent the value of a number.

VARIABLE - the unknown
- use a letter to represent a number

CONSTANT - the integer in an algebraic expression or equation

ONE STEP ALGEBRA:

1.) Isolate the variable.
2.) Cancel using the opposite.
-Create a zero pair for the constant.
3.) Balance on the other side of the equal sign.
4.) Verify your answer.

ADDITION

SUBTRACTION

MULTIPLICATION

DIVISION

2 Step Equations

1.) Isolate the variable.
2.) Cancel the constant.
3.) Balance.
4.) Simplify the variable.
5.) Balance

EXAMPLES:




VIDEOS:










LINKS:





Wednesday, March 9, 2011

Kathryn's Great Big Book of Integers


CHAPTER 1 GRADE 7 INTEGERS REVIEW

(+4)+(-2)=+2
positive 4 AND negative 2
have 4 AND owe 2

STANDARD FORM (remove the + and () when not needed)
(+4)+(-2)=2
remove the brackets and the + sign because they aren't needed for the equation.
4-2=-2
have 4, owe 2=2

MAKE A ZERO PAIR
a) -16, +16 b) -5,+5 c)-11,+11 d)-2,+2
e) -6,+6 f) -10,+10 g) -9,+9 h) -3,+3

Homework:
5. -3-(-7) =+4
Owe 3 owe 7= +4
To solve this problem, use zero pairs


6. -3-7= -10
Owe 3 and owe 7= -10
To solve add -3 and -7 then you'll have -10

7. 3-7 = -4
Have 3, owe 7 = -4
To solve use zero pairs. Then remove -7. Lastly, check if there's any zero pairs.

8. 3+7 = 10
Have 3 and have 7= 10
To solve, add 3 and 7.

9. -3+7= +4
Owe 3 and have 7= +4
To solve, use zero pairs. Remove zero pairs.

CHAPTER 2- MULTIPLYING INTEGERS

(+2)x(+3) = +6
(2)x(3) = 6
(2)(3) = 6
*Standard form*2(3) = 6

(+2)x(+3) = +6
2 groups of (3)=+6


(+2)x(-3) = -6
2 groups of (-3)=-6


(-2)x(-3) = +6
remove 2 groups of (-3)=+6


(-2)x(+3) = -6
remove 2 groups of (+3)=-6


Sign Rule (negative signs):Even = When you have an even number of negative factors, the product is positive.Odd = When you have an odd number of negative factors, the product is negative.

CHAPTER 3- DIVIDING INTEGERS

Partitive Division- a type of division which means making parts

EX: 6÷3=2

(-6)÷-3 =2

Quotative- a type of division where you share your total with groups.

EX: -6÷(2)=

CHAPTER 4- Order of Operations With Integers

To solve (+5) x (-3) + (-6) ÷ (+3)=
*Squared brackets ALWAYS come first
*If there's no squared brackets use the order of BEDMAS.
*If there is division and multiplication at the same time, answer from left to right.
*If there is addition and subtraction at the same time, answer from left to right.
*Remember the sign rules!:)

STILL IN TROUBLE?

LINKS:)
http://www.mathleague.com/help/integers/integers.htm
http://www.mathgoodies.com/lessons/vol5/intro_integers.html

VIDEOS



Sunday, March 6, 2011

Term 2 Reflection

For term 2, I think I did well on Total Surface Area. I think did well on it because I did all my home works and I got high grades in the quizzes Mr.Harbeck gave us.Also, because I listened in class and apply all the math work needed. For this term, I struggled a bit in drawing nets for 3d objects.However, after asking questions and a bit of practice, I got better. For next term, I will try to not procrastinate, finish all my work, and comment frequently on the blogs my classmates will make. Also, I will ask questions if I am not certain of something.

I learn a lot about Percent, Total Surface Area, and Volume. I learned how to find and combine percents. I also learned how to know which stores have better deals and save more money. I got confused at times and made mistakes but I learned from them. For Total Surface Area, I learned how to draw nets for different prisms and cylinder. Plus, I learned how to find the total surface area by using variety of formula. At first I struggled so much on drawing the nets. However with the help of my friend, I learned how to draw them without any help. I also learned how to find volume of shapes.Though it’s quite confusing at first, with practice, I started to solve problems independently.

AUDIOBOO!


*I messed up "variety"

Thursday, January 27, 2011

Homework Book Page 52-55

Questions: #2 on page 54, #4 on page 55 & #6 on page 55.

2) I was asked to find the surface area of this.
A)
My solution is :


lxw= a
3.2x11.5= 36.8cm²
3.2x11.5= 36.8cm²
5x11.5=57.5cm²
5x11.5=57.5cm²
5x3.2=16cm²
5x3.2=16cm²

TSA= (36.8X2)+(57.5X2)+(16X2)
TSA=220.6cm²

B)

My solution:
lxw=a
4.5x10.4=46.8 cm²
4.5x10.4=46.8 cm²
12x10.4=124.8 cm²
12x10.4=124.8 cm²
12x4.5=54 cm²
12x4.5=54 cm²

TSA=(46.8x2)+(124.8x2)+(54x2)
TSA= 451.2 cm²

4) Ty is painting this storage bench for the deck. How much area does he need to paint, to the nearest hundredth of a square meter?

My solution:
lxw=a
0.5x1.56=0.78m²
0.5x1.56=0.78m²
0.38x1.56=0.5928m²
0.38x1.56=0.5928m²
0.5x0.38=0.19m²
0.5x0.38=0.19m²

TSA=(0.78X2)+(0.5928X2)+(0.19x2)
TSA=3.1256m²

6) A)Calculate the amount of material hey need to make a new cover.


My solution:
TSA= 2.992+2.992+0.88+0.88
TSA= 7.744m²

B) Waterproof material at the Fabric Warehouse is on sale this week for $24.95 per square metre. Calculate the cost to make he new cover.

Solution:
7.774 X 24.95= 193.96
The cost to make a new cover is $193.96.

VIDEOS!:)



LINKS:


What is a surface area?

What is the total surface of a triangular prism?
*Please tell me if a mistake was made.
* Photos aren't as clear as always. The camera I'm using often isn't available to use.
___________________________
VOLUME PROBLEMS

r=d/2 The maximum volume is 3.925m³
r=0.5/2
r=0.25m

V=Ï€.r.r.h
V= 3.14 x 0.25 x O.25 x 20
V=0.19625m² x 20m
V=3.925m³
____________________
CYLINDER VOLUME

r=d/2 r=d/2
r=1/2 r=0.8/2
r=0.5m r=0.4m

V=Ï€.r.r.h V=Ï€.r.r.h
V=3.14x0.5 x0.5 x 10 V=3.14x0.4 x0.4 x 10
V=0.785m²x 10m V=0.5024m²x 10
V= 7.85m³ V=5.024m³

7.85m³-5.024m³=2.826m³ The required concrete is 2.826m³ or 2.8m³


VOLUME VIDEO! ENJOY!:)

Sunday, January 16, 2011

Kathryn's Final Percent Post

Percent-means out of 100. Another name for hundredths.
ex. 88% means 88 out of 100 or 88/100 or 0.88 .

4.1 Representing Percents
Means showing a percent as a picture in a hundred grids.
EX: 24% on a hundred grid 24 squares would be shaded, so it is 24%


4.2 Fractions, Decimals,Percents
Fractions, decimals, and percents can be used to represent numbers
in various situations. Percents can be written as fractions and as decimals.

EX: 50%= 0.5= 1/2

4.3 Percent of a Number
Can use mental math strategies such as halving, doubling, and dividing by ten to find the percent of some numbers.
To calculate the percent of a number, write the percent as a decimal then multiply by the number.

EX:300% of 2000: 300÷100=3
2000x3=6000

4.4 Combining Percents
Percents can be combined by adding to solve problems.
EX: 5%+6%= 11%

To calculate the increase of a number
You can add the combined amount to the original number.
EX: 12% of 100= 0.12 x 100 =12
100+12=112

You can multiply the original number by a single percent greater than 100.
EX: 112% of 100 = 1.12 x 100
=112

PERCENT VIDEO! ENJOY:)