Chapter 1 Grade 7 Integer Review
(+4) + (-2) = +2
Positive (4) and Negative (2) = positive 2
have 4 and owe 2 = have 2
Standard Form: 4 - 2 = -2
Make zero pairs:
-16 = +16, -5 = + 5, +6 = -6, -2 = +2,
-10 = +10, +3 = -3, +11 = -11, -9 = +9
CHAPTER 2
(+2)x(+3) = +6
Positive (4) and Negative (2) = positive 2
have 4 and owe 2 = have 2
Standard Form: 4 - 2 = -2
Make zero pairs:
-16 = +16, -5 = + 5, +6 = -6, -2 = +2,
-10 = +10, +3 = -3, +11 = -11, -9 = +9
CHAPTER 2
(+2)x(+3) = +6
(2)x(3) = 6
(2)(3) = 6 *Standard form*
2(3) = 6
(+2)x(+3) = +6
2 groups of (3)=+6
(+2)x(-3) = -6
2 groups of (3)=+6
(+2)x(-3) = -6
2 groups of (-3)=-6
(-2)x(-3) = +6
remove 2 groups of (-3)=+6
(-2)x(+3) = -6
remove 2 groups of (+3)=-6
Sign Rule (negative signs):
Even = When you have an even number of negative factors, the product is positive.
Odd = When you have an odd number of negative factors, the product is negative.
Chapter 3 Dividing Integers
Sign Rule: If you have no negative or an even number of negative signs in a division question, the quotient is positive.
There are 2 types of division
Partitive Division or making parts
6÷3=2 ,
how many groups of 3 are in 6?
Quotative Division or sharing your total with groups
6÷3=2 , share 6 with 3 groups
6÷2 and -6÷ (-2) will give you the answer of 3 because the questions has no, or an even amount of negative signs.
(-6)÷2 and 6÷(-2) will give you the answer of -3 because the questions have an odd amount of negative signs.
Chapter 4 Order of Operations with Integers
Brackets Exponents Division Multiplication Addition Subtraction
(+5) x (-3) + (-6) ÷ (+3)
(+5) x (-3) + (-2) [solved division first]
(-15) + (-2) [solved multiplication after]
= (-17) [solved addition]
