Mike's 2minute First Draft Video

We have some mistakes and missed some parts we had to add to our video, but we will fix it before the final draft. Enjoy.

Mike's Algebra Post

Algebra - Writing mathematical phrases using letters to represent numbers.
Variable - A letter that represents a number in an algebraic expression or equation.
Constant - The integer in an algebraic equation or expression.
Equation - Only has one answer and has an equal sign (=).


Solving an Algebraic Equation:
1) Isolate the variable
2) Cancel the constant using zero pair
3) Balance, doing it to both sides
4) Verify to check

One Step Equation:
















Two Step Equation:
1. Isolate the variable
2. Cancel the constant
3. Balance
4. Simplify the variable
5. Balance
6. Verify
































A website that might help you understand more.

Mike's Great Big Book of Integers

Chapter 1
Grade 7 Integer Review:


(+4)-(-4)
This means you have a zero pair
(+4)-(-4)=0


(+6) + (-2) = +4
Positive 6 and Negative 2 = Positive 4
You have 6 and you owe 2 = have 4








Making Zero Pairs:


-6=+6

-21=+21

-42=+42

-65=+65

-11=+11

-14=+14

-63=+63



Chapter 2
Multiplying Integers:

SIGN RULE:
Even: When you have a even number of negative factors the product is positive.
Odd: When you have a odd number of negative the product is negative.





(+2)x(-3)=
2 groups of (-3)=(-6)
























(+2)x(+3)
2 groups of (+3)=(+6)





















(-2)x(+3)
2 groups of (+3)=-6











(-2)x(-3)=
2 groups of (-3)=6










Chapter 3
Dividing integers:

SIGN RULE:
If you have no negative or an even number of negative signs in a division question, the quotient is positive.

There are 2 types of division:
One of them is,
Partitive division:
Partitive division is making parts.
Example:
6 divided by 2= 3

6 divided by -2= -3

The Other on is,
Quotative division:
Quotative division is sharing your total, with groups.
Example:
(-6) divided by 2= -3

6 divided by (-2)= +3

Chapter 4
Order Of Operations:
Use Badmas.
B =stands for brackets
E =stands for exponents
D =stands for division
M =stands for multiplication
A =stands for addition
S =stands for subtraction
First solve any brackets, then exponents, then any divide, then multiply, then add, and lastly, subtract.



If I had to solve this problem:
(+5) x (-3) + (-6) ÷ (+3)=
First I would put brackets around, (-6)÷(+3). Then solve it.
[(-6)÷(+3)]=(-2)
Now the question would be:
(+5) x (-3) + (-2)=
Using the BEDMAS rules, exponents are next, but there is none. So we move on to multiplication:
(+5) x (-3)= (-15)
The question is now:
(-15) + (-2)=
Lastly you will answer it:
(-15) + (-2)= (-17)

Term 2 Reflection

In Term 2, I did very well in the finding out the volume of shapes ( prisms, and cylinders ) We have to follow the formula, (pi x r x r)x h. I understood how to do it because I practiced at home and got help from my friends, which really helped me .

I struggled in percents the most because I did not understand it, I also struggled in volume because I couldn't remember the formulas. In Term 3, I would like to work harder on assignments, and homework. I would like to focus and demonstrate that I am learn. I also would like to do all of my computer work, so I will do better this in this Term. In term 2 i slacked off a lot and was easily distracted, this term I would like to be reminded if I a , and focus in my work. Therefore, I would like to sit with my usual friends, because they have helped me and explain what I was doing wrong. I am more comfortable doing work and homework with my friends, because they are very helpful and demonstrate good role models for me.

I learned a lot this term about percents, surface area, and volume such as all the formulas that are involved. And how to use the formulas correctly, so i wont mess up.

Volume Post

Chapter 7.4













Inside Circle:

r=d÷2 V=pi.r.r.h
r=8÷2 V=(3.14x4x4)x40
r=4cm V=2009.6cm³


Outside Circle:

r=d÷2 V=pi.r.r.h
r=10÷2 V=(3.14x5x5)x40
r=5cm V=3140cm³
3140cm³-2009.6cm³=1130.4cm³


Chapter 7.3

Jumbo:

r=d÷2 V=pi.r.r.h
r=20÷2 V=(3.14x10x10)x40
r=10cm V=12,560cm³

Popcorn Lover's:

r=d÷2 V=pi.r.r.h
r=30÷2 V=(3.14x15x15)x20
r=15cm V=14,130cm³


Martha should buy the popcorn lover's one because it has more volume than the jumbo one.Popcorn Lover's volume is 14,130cm³ while Jumbo's 12,560cm³

Mike's Volume Post

Show You Know

A) Area of Base X Height
L x W x H

8.5cm x 4cm x 5cm

170cm3









B) L x W x H

3cm x 3cm x 3cm 3 x 3 = 9cm2

9cm2 x 3cm = 27cm3








C)
B x H
----- = H
2

9 x 5
----- = 22.cm2
2

22.5cm2 x 8cm = 180cm3

OR

5 x 9 x 8/2 = 180cm3

A website you can visit about volume.

Mike's Final Percent Post

A percent means out of 100 , another name for hundredths and can be expressed as decimals or fractions.



REPRESENTING PERCENTS
Shade squares on a grid of 100 squares called a hundred grid to represent a percent. A completely shaded grid represents 100%. If you shade more than one grid, that represents a percent greater than 100%. To represent a fractional percent between 0% and 1%, you have to shade part of one square. Also, to represent a fractional percent greater than 1% you have to shade squares from the hundred grid to show the whole number, then shade part of a square the grid to show the fraction.





PERCENT OF A NUMBER

Use mental math strategies such as doubling, halving, and dividing by 10 to find the percents of some numbers. Write the percent as a decimal and then multiply by the number.

Example:14 1/2% of 60 = 0.145z60 = 8.7

COMBINING PERCENTS

Adding Percents can solve problems.

To calculate the increase in any number, add the combined percents to the original number.

Example: 30% of 100=0.30x100=30, 30+100=130

Or multiply.

Example:130% of 100 = 1.30x 100= 115

Percents of percents can be used to determine amounts that result from consecutive increases or decreases.

Percent Review Video:

Here's a video about 'Percents'

Mike's Pay It Forward

Part 1:

The 11-year old boy, Trevor, living with his alcoholic mother. An assignment assigned by Mr. Simonet, his social studies teacher, the assignment was to think of something to change the world and make it happen. Trevor's idea was to help three people, and the 3 people will try to pay it forward to three other people; His effort to make a difference affected people in his life, and people that he doesn't even know.

Walking to the Church

Part 2:

For my act of kindness, my group and I (Cameron, Kaecee, Ryan, And Daniel) decided to donate used and new toys. We decided to donate toys because we have toys that we don't use anymore, and its almost Christmas. We donated the toys to 'Helping Hand Foundation' which gives the toys to immigrate families in Winnipeg. We donated the toys on December 17th at 12:00 PM.

The Church we donated to. (Helping Hand Foundation)

Part 3:

Our act of kindness went well because we gathered all of our unwanted toys and donated it all. We went to a church that sends toys to immigrate families, and then we asked the clerk if she knew what Pay It Forward is, also asked her if she would Pay It Forward. When we donated the toys, I felt joyful because I knew it will go to a children that might not afford toys, and that the children will have a good childhood memory.The Clerk was happy and shocked that five boys are donating toys to their foundation, and that we are helping out our community.

Part 4:

The idea of Pay It Forward is that we can help out people step by step, and maybe they will do the same for others in need. I think my act of kindness made a difference in children's lives because they will have something for Christmas and will remember having a good Christmas when they're older.

PAY IT FORWARD !

Pages 135 - 136 Odds

1. Jordan is right. To convert a decimal to a percent you must multiply by 100.
0.003 x 100= 0.30.3%

3. Both Mark and Jonas are correct. The simplest answer is that Mark and Jonas' team scored 5 while their opponent scored 1.

Mark's team scored 5 goals while the other team scored 1.

Notice that there is 500/100 which is 500% like Mark said and that you multiply thedenominator by 5 to get the numerator like Jonas said.

5. Answer in the picture and also simplified.

7. Answer in the picture and also simplified.

9. Answer in the picture and also simplified.

A Video of converting fractions, decimals and percents:

Here is a Link for "converting fractions, decimals and percents".

Michael' s Pythagoras Scribe Post

H.W For The Weekend : Pages 91 - 94

The Question Answers:

1.) In a relation the areas of the triangles is that the first and also second triangle have the squares on the the side to show the areas of (a, b, c). The last triangle as you can see does not contain the squares around it.

6.) A) 25 + 144 = 169
B) 5cm, 12cm, 13cm
C) The sum of all the areas of both smaller squares will be equal to the largest one, 5 2 + 12 2 = 13 2


13.) I think no, The garden is not a right triangle, the sum of all the areas of the smaller squares is not equal to the area of the largest square there, 4800 + 4800 does not equal 9800, it equals 9600.

20.) The sum of the areas of the two smaller semi-circles is equal to the area of the semi-circle on to the Hypotenuse of the triangle.


Tell me if there is any mistakes I have made.





Here is a link for even more help on math

http://www.yourteacher.com

Mike's Sesame Street Video

Michael's math profile.

Hey, I'm Michael, and I am a grade 8 math student . If someone asked me if I like math, I would say 'kind of' because sometimes it's easy for me to learn, but at the same time hard to understand. The thing I liked the most in math class, was doing the spinners for circle graphs, and we would all guess which colour it was going to land on !

Last year in grade 7, my favourite unit we studied, was fractions, because it was really easy, and we learned how to add and subtract them. I did well in this unit because, it was very easy for me to understand what was going on, and what was going to come next. The unit I had a hard time was converting the decimals, because sometimes I would get confused.

This year, in grade 8 math, I will become successful, by studying hard and finishing all my homework and getting good grades on tests. I would like to learn more about algebra, and anything else that's new to us and become a better and smarter student for all units.

My favourite blog I did last year, was the one I first did, because it was the day we first learned how to blog and I think I improved throught the year. Blogging helped me a lot because we gave and got feedback from our classmates saying what we can do better next time. I want to do more blogging this year, and just have fun !