*Chapter 1: Grade 7 Integer Review*

(+4) + (-4) = 0

^ have four ^ owe four

(+2) + (-2) = 0

^ have two ^ owe two

Brackets are training wheels.

+4 + -4+4 - 4

4 - 4 = 0 (

*pure standard form)*

*zero pair: is a pair of the same negative number, and positive number. Together, they equal 0.*

Making Zero Pairs:

a) -16=+16 b) -6=+6 c) -10=+10 d) +19=-19 e) -11=+11 f) -14=+14 g) -63=+63

Making Zero Pairs:

a) -16=+16 b) -6=+6 c) -10=+10 d) +19=-19 e) -11=+11 f) -14=+14 g) -63=+63

1. -3 - (-7) = +4

use zero pairs and remove 3 groups of (-7) leaving you with 4 positives

2. -3 -7 = -10

Two negatives equal a positive so you just combine the two without zero pairs leaving you with -10

3. 3 -7 = -4

Use zero pairs and remove 3 groups of 7 (-21) which leaves you with 4 negatives

4. 3 +7 = +10

Since they're both positives, just add them together normally

Chapter 2: Multiplying Integers

(+2) x (+3)= +6

When multiplying two positives, the answer will be positive so just multiply them like usual.

(+2) x (-3)= -6

(-2)

(+3)=

Remove 2 groups of (+3)

*Remove 2 groups of (-3)*

**Sign Rule ( Negative Signs )**Even= when you have an even number of negative factors the product is positive.

Negative = When you have an odd number of negative factors the product is negative.

Chapter 3: Dividing Integers

2 types of division

6÷3=2

How many groups of (+3) are in 6?

*

**Partitive division or making parts**6

÷3=2

Share 6 with 3 groups

6

÷2=3

-6

÷(-2)= -3

(-6)

÷2= -3

6

÷(-2)= -3

*When you have an odd number of (-) signs in a division question, the quotient (answer ) is gonna be negative*

Chapter 4: Order of Operations with Integers

I'm going to show you how to solve this question:

[(+5) x (-3)] + [(-6) ÷ (+3)]=

= 5 x -3 + -2

= -15 + -2

= -17

If you follow the rule of BEDMAS

B= Brackets

E= Exponents

D= Division

M= Multiplication

A= Addition

S= Subtraction

You should get the right answer

Here are 2 videos to help you out

## No comments:

## Post a Comment