## Monday, March 7, 2011

### Diorella's Great Big Book of Integers

Chapter 1: Grade 7 Integer Review

(+4) + (-4) = 0
^ have four ^ owe four
(+2) + (-2) = 0
^ have two ^ owe two
Brackets are training wheels.
+4 + -4+4 - 4
4 - 4 = 0 (pure standard form)

zero pair: is a pair of the same negative number, and positive number. Together, they equal 0.
Making Zero Pairs:
a) -16=+16 b) -6=+6 c) -10=+10 d) +19=-19 e) -11=+11 f) -14=+14 g) -63=+63

1. -3 - (-7) = +4
use zero pairs and remove 3 groups of (-7) leaving you with 4 positives
2. -3 -7 = -10
Two negatives equal a positive so you just combine the two without zero pairs leaving you with -10
3. 3 -7 = -4
Use zero pairs and remove 3 groups of 7 (-21) which leaves you with 4 negatives
4. 3 +7 = +10
Since they're both positives, just add them together normally

Chapter 2: Multiplying Integers
• (+2) x (+3)= +6
• When multiplying two positives, the answer will be positive so just multiply them like usual.

• (+2) x (-3)= -6
• 2 groups of (-3)

• (-2)
• (+3)=
• Remove 2 groups of (+3)
• (-2) x (-3)=
• Remove 2 groups of (-3)

Sign Rule ( Negative Signs )
Even= when you have an even number of negative factors the product is positive.
Negative = When you have an odd number of negative factors the product is negative.

Chapter 3: Dividing Integers

2 types of division
6÷3=2
How many groups of (+3) are in 6?
*Partitive division or making parts

6
÷3=2
Share 6 with 3 groups

6
÷2=3
-6
÷(-2)= -3
(-6)
÷2= -3
6
÷(-2)= -3

When you have an odd number of (-) signs in a division question, the quotient (answer ) is gonna be negative

Chapter 4: Order of Operations with Integers

I'm going to show you how to solve this question:
[(+5) x (-3)] + [(-6) ÷ (+3)]=
= 5 x -3 + -2
= -15 + -2
= -17
If you follow the rule of BEDMAS
B= Brackets
E= Exponents
D= Division
M= Multiplication