GRADE 7 INTEGER REVIEW.
  
 and ____negative 2
 _____owe 2

___positive 4
___have 4
STANDARD FORM:
42= 2
Make zero pairs:
a) 16 = +16
b) +6 = 6
c) 5 = +5
d) 10 = +10
e) +11 = 11
f) 9 = +9
g) 2 = +2
h) +3 = 3
6 +2 = 4
6 2 = 8
6 +10 = +4
a) 6 (4) = +10
b) 36 = 9
c) 2(3) = +1
SUBTRACTION= adding a negative integer
HOMEWORK:
6(4) = 2
10+6 = 4
67+2 = +11
14(3) = +17
* 3(7) = +4
* 37 = 10
* 37 = 4
* 3+7 = +10
* 3+7 = +4
CHAPTER TWO:
MULTIPLYING INTEGERS.
(+2) x (+3) or 2 groups of (+3) = 6
OF normally means multiplying in word problems.
(+2) x (3) = 6
(2) x (+3) = 6
(2) x (3) = +6
(3) x (4) = +12
DO page. 289 Show You Know
and page 290290 odd numbers only
HOMEWORK BOOK page 9091
NUMBER LINE:
(+2) x (+3) = 6
(+2) x (3) = 6
Seatwork:
0(+4) x (+5) = +20 o (+5) x (+4) = +20
1(2) x (+3) = 6 1(+3) x (2) = 6
2(1) x (6) = +6 2(4) x ( 5) = +20
(1) x (6) x (1) x (1)
+6 x (1) = 6 x (1) = 6
SIGN RULE (negative signs):
EVEN when you have an even number of negative factors, the product is positive.
ODD when you have an odd number of negative factors, the product is negative.
HOMEWORK:
DO page 297  textbook
page 9293  homework book
LINKS:
CHAPTER 3:
DIVIDING INTEGERS:
Two Types of Division
6/3 = 2
How many groups of (+3) are in +6?
PARTATIVE DIVISION or Making Parts
6/3 = 2
Share 6 with 3 groups
QUOTATIVE DIVISION or Sharing Your Total with Groups
(6) / (3) = 2
How many groups of (3) are in 6
Only partative will work.
6 / 3 = 2
2 x 3 = 6
3 x 2 = 6
(6) / (3) = 2
2 x (3) = 6
(3) x (2) = 6
If you have no negative or an even number of negative signs in a division question, the quotient is positive.
6 / 3 =  2
Share (6) with 3 groups
QUOTATIVE DIVISION
6 / (+3) = (2)
(2) x (+3) = 6
(+3) x (2) = 6
6 / (3) = 2
When you have an odd number of (  ) signs in a division question, the quotient is negative.
You'll see something like:
ORDER OF OPERATIONS WITH INTEGERS
When solving integer problems, you need to know or decide what operation to perform.
The order of operations for integers is the same as for whole numbers and decimals.
You should always solve an integer expression or equation by:
1. Brackets. (IF there's a square bracket, do that first then the round bracket)
2. Multiply and divide in order, from left to right.
3. Add and subtract in order, from left to right.
To solve the equation :
(+5) x (3) + (6) ÷ (+3),
You have to follow the rules I listed up top. But as you see, the brackets used in that expression was only used as a guide, so you don't have to do something about that. So first, multiply (+5) to (3) and you'll get (15). Now, divide (6) and (+3) and you'll get (2). Lastly, add (15) and (2) and you'll get (17) as your final answer.
Still having a hard time solving this? Check out this links to help you with the Order of Operations.
http://www.mathgoodies.com/lessons/vol5/intro_integers.html
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