**Chapter 1***Grade 7 Integer Review:*

(+4)-(-4) =0

Positive 4 subtract Negative 4 = 0

You have 4 and you owe 4 = 0 or none

(+6) + (-2) = +4

Positive 6 and Negative 2 = Positive 4

You have 6 and you owe 2 = have 4

Zero Pairs:

-6=+6

-20=+20

-10=+10

-5=+5

-1=+1

-4=+4

-50=+50

**Chapter 2**

Multiplying Integers:**SIGN RULE**:

*Odd*: When you have a odd number of negative the product is negative.

*Even*: When you have a even number of negative factors the product is positive.

(+2)x(-3)=

2 groups of (-3)=(-6)

**Chapter 3***Dividing integers:*

**SIGN RULE:**

If you have no negative or an even number of negative signs in a division question, the quotient is postive.

There are 2 types of division:

**Partitive division:**

Partitive division is making parts.

Example:

6 divided by 2= 3

6 divided by -2= -3

**Quotative division:**

Quotative division is sharing your total, with groups.

Example:

(-6) divided by 2= -3

6 divided by (-2)= +3

**Chapter 4**

Use Badmas:

B ...stands for brackets

E ...stands for exponents

D ...stands for division

M ...stands for multiplication

A ...stands for addition

S ...stands for subtraction

(Use in order)

If I had to solve this problem:

(+5) x (-3) + (-6) ÷ (+3)=

First I would put brackets around, (-6)÷(+3). Then solve it.

[(-6)÷(+3)]=(-2)

Now the question would be:

(+5) x (-3) + (-2)=

Multiplication is next:

(+5) x (-3)= (-15)

Now Answer:

(-15) + (-2)= (-17)

## No comments:

## Post a Comment