## Monday, March 7, 2011

### Marie's Great Big Book of Integers

Chapter 1 Grade 7 Integer Review

(+4) + (-2) = 2
+4 = positive 4, have 4
+ = and
-2 = negative 2, owe 2
Have 4 and Owe 2 = Have 2

Standard Form
4 - 2 = 2

Make zero pairs:
-16 +16
-5 +5
-11 +11
-2 +2
+6 -6
-10 +10
-9 +9
-5 +5

-6 +2 = -4

-6 -2 = -8

-6 +10 = +4

6 - (-4) = 10

-2 - (-3) = 1

-3 -6 = -9

-3 -2 = -5
3 -2 = Subtraction = adding a negative integer

Homework:

-6 - (-4) = -2
-10 +6 = -4
6 -7 +2 = +1
14 - (-3) = +17

-3 - (-7) = +4
-3 -7 = -10
3 -7 = -4
3 +7 = +10

Chapter 2: Multiplying Integers

(+2)x(+3) = +6
(2)x(3) = 6
(2)(3) = 6 *Standard form*
2(3) = 6

(+2)x(+3) = +6
or 2 groups of (+3)

(+2)x(-3) = -6
or 2 groups of (-3)

(-2)x(-3) = +6
or remove 2 groups of (-3)

(-2)x(+3) = -6
or remove 2 groups of (+3)

Sign Rule (negative signs):
Even = When you have an even number of negative factors, the product is positive.
Odd = When you have an odd number of negative factors, the product is negative.

Chapter 3: Dividing Integers

Partitive Division or making parts:
6 ÷ 2 = How many groups of (+2) are in 6?
There are 3 groups of 2 in 6.

(-6) ÷ (-2) = How many groups of (-2) are in -6?
There are 3 groups of (-2) in -6.

Quotative Division or sharing your total with groups.
(-6) ÷ 2 = Share -6 with 2 groups.

6÷2= and -6÷ (-2)= will be positive because if you have no negative or an even number of negative signs in a division question, the quotient is positive.

(-6)÷2= and 6÷(-2)= will be negative because when you have an odd number of negative signs in a division question, the quotient is negative.

Chapter 4: Order of Operations with Integers

BEDMAS = Brackets, Exponents, Division, Multiplication, Addition, Subtraction

(+5) x (-3) + (-6) ÷ (+3)=

First, you would need to use square brackets to separate the equation.
[ (+5) x (-3) ] + [ (-6) ÷ (+3) ] =
This step causes the equation easier to solve.

Next, you solve what's inside the square brackets.
(-15) + (-2) =