Chapter 1: Grade 7 Integer Review
(+2) x (+3)= +6 When multiplying two positives, the answer will be positive so just multiply them like usual.
(+2) x (-3)= -6
(-2) (+3)= Remove 2 groups of (+3)
(+4) + (-4) = 0
^ have four ^ owe four
(+2) + (-2) = 0
^ have two ^ owe two
Brackets are training wheels.
+4 + -4+4 - 4
4 - 4 = 0 (pure standard form)
zero pair: is a pair of the same negative number, and positive number. Together, they equal 0.
Making Zero Pairs:
a) -16=+16 b) -6=+6 c) -10=+10 d) +19=-19 e) -11=+11 f) -14=+14 g) -63=+63
Making Zero Pairs:
a) -16=+16 b) -6=+6 c) -10=+10 d) +19=-19 e) -11=+11 f) -14=+14 g) -63=+63
1. -3 - (-7) = +4
use zero pairs and remove 3 groups of (-7) leaving you with 4 positives
2. -3 -7 = -10
Two negatives equal a positive so you just combine the two without zero pairs leaving you with -10
3. 3 -7 = -4
Use zero pairs and remove 3 groups of 7 (-21) which leaves you with 4 negatives
4. 3 +7 = +10
Since they're both positives, just add them together normally
Chapter 2: Multiplying Integers
Remove 2 groups of (-3)
Sign Rule ( Negative Signs )
Even= when you have an even number of negative factors the product is positive.
Negative = When you have an odd number of negative factors the product is negative.
Chapter 3: Dividing Integers
2 types of division
6÷3=2
How many groups of (+3) are in 6?
*Partitive division or making parts
6
÷3=2
Share 6 with 3 groups
6
÷2=3
-6
÷(-2)= -3
(-6)
÷2= -3
6
÷(-2)= -3
When you have an odd number of (-) signs in a division question, the quotient (answer ) is gonna be negative
Chapter 4: Order of Operations with Integers
I'm going to show you how to solve this question:
[(+5) x (-3)] + [(-6) ÷ (+3)]=
= 5 x -3 + -2
= -15 + -2
= -17
If you follow the rule of BEDMAS
B= Brackets
E= Exponents
D= Division
M= Multiplication
A= Addition
S= Subtraction
You should get the right answer
Here are 2 videos to help you out
No comments:
Post a Comment
Note: Only a member of this blog may post a comment.