Diana's Great Big Book of Integers

Chapter 1
Grade 7 Integer Review:


(+4)-(-4) =0
Positive 4 subtract Negative 4 = 0
You have 4 and you owe 4 = 0 or none

(+6) + (-2) = +4
Positive 6 and Negative 2 = Positive 4
You have 6 and you owe 2 = have 4

Zero Pairs:

-6=+6

-20=+20

-10=+10

-5=+5

-1=+1

-4=+4

-50=+50

Chapter 2
Multiplying Integers:

SIGN RULE:
Odd: When you have a odd number of negative the product is negative.
Even: When you have a even number of negative factors the product is positive.




(+2)x(-3)=
2 groups of (-3)=(-6)

(+2)x(+3)=
2 groups of (+3)=(+6)



(-2)x(+3)
2 groups of (+3)=-6

(-2)x(-3)
2 groups of (-3)=6

Chapter 3
Dividing integers:
SIGN RULE:
If you have no negative or an even number of negative signs in a division question, the quotient is postive.

There are 2 types of division:
Partitive division:
Partitive division is making parts.
Example:
6 divided by 2= 3

6 divided by -2= -3


Quotative division:
Quotative division is sharing your total, with groups.
Example:
(-6) divided by 2= -3

6 divided by (-2)= +3

Chapter 4

Use Badmas:
B ...stands for brackets
E ...stands for exponents
D ...stands for division
M ...stands for multiplication
A ...stands for addition
S ...stands for subtraction
(Use in order)

If I had to solve this problem:
(+5) x (-3) + (-6) ÷ (+3)=
First I would put brackets around, (-6)÷(+3). Then solve it.
[(-6)÷(+3)]=(-2)
Now the question would be:
(+5) x (-3) + (-2)=
Multiplication is next:
(+5) x (-3)= (-15)
Now Answer:
(-15) + (-2)= (-17)