Kathryn's Homework 3,7,11

3)



ANSWER:
a) 420 m. I added the length and width .

b) a²+ b²=c²
300²+120²=c²
(300X300)+(120X120)=c²
90000m²+14400m²=c²
104400m²=c²
√104400m²=c
323.10m=c


c) 420m-323.10= 97.10 m
Maria walked farther by 97.10 meters.


7)

ANSWER :

a²=c²-b²
a²=80²-79²
a²=(80X80)-(79X79)
a²=6400cm²-6241cm²
a²=159cm²
a=√159cm²
a=12.61cm


11)

The maximum length of the ladder is 291.71cm and the minimum length is 291.10.

LINKS:

INFORMATION
EXERCISES

VIDEO:

PLEASE LET ME KNOW IF MISTAKES WERE MADE. THANK YOU:))

AJ's Scribe Post

Questions 3,9,14.

3.

A)420m

120m+300m = 420m

B)323m

a²+b²=c²

120m²+300m²=c²

(120x120)+(300x300)=c²

104400m²= c²

√104400m²= c²

√323²= √c²

C) Maria walked further by 97m

9.

A)4.2cm

B)34cm

14.

15.6mm

Cameron's Homework Book Post: pg. 33 Numbers 6,7,8

I have chosen to do questions 6, 7, and 8 in the homework book on page 33.

6. The width of a rectangle is 8cm, and its diagonal is 17cm.

a) Calculate the length of the rectangle. Show your work!
c² - b² = a²
17² - 8² = a²
(17x17) - (8x8) = a²
289cm² - 64cm² = 225cm²
225cm² = c²
√225cm² = √c²
15cm² = c²


7. A quadrilateral has a width of 17cm and a length of 26cm. A diagonal is 31cm. Is the quadrilateral a rectangle? Justify your answer.

a² + b² = c²
26² + 17² = c²
(26x26) + (17x17) = c²
676cm² + 289cm² = 965cm²
965cm² = c²
√965cm² = √c²
31.06cm²

Answer: No, the corners do not meet at right angles because 17² + 26² ≠ 31²


8. A ship leaves port heading due west. After travelling at a speed of 20 km/h for 10h, the ship makes a 90 degree turn and heads south, travelling south for 7.5 h, how far is the ship from the port? Show your work.

20 km/h for 10h west equals 200km
20 km/h for 7.5h south equals 150km
200 km² + 150km²=?
40,000km + 22,500km = 62500km
✓62,500km = 250km²

Answer: The ship is 250km² away from the port.

Here is a video:




Heres a link:
http://www.mathsisfun.com/pythagoras.html

Heres a game to help you:
http://www.kidsnumbers.com/pythagorean-theorem-game.php

I'm sorry that their aren't any pictures, my computer won't let me put them on.

Hope this helps!

Pythagoras Textbook Number 15

#15 The coordinate grid shown was drawn on centimetre grid paper. What is the length of line segment AB? Express your answer to the nearest tenth of a centimetre.

















Answer:

















I got 2 cm for side a and i got 4 cm for side b because i counted the units AB were taking up on the graph paper vertically and horizontally.




PS:

I know i wasn't assigned this scribe but Thessa didn't have the answer so I just wanted share what i got if people were curious about the answer.. I'm not exactly sure if I'm right but there you go (: sorry harbeck !

Link: http://www.mathsisfun.com/pythagoras.html


Video:

Pythagoras Textbook Questions and Answers

5, 8, 11, and 14!

QUESTION #5:

a) What is the area of each square attached to the legs of the right triangle?

b) What is the area of the square attached to the hypotenuse?

c) What is the length of the hypotenuse?

ANSWER:
a.) 6 x 6 = 36

8 x 8 = 64

b.)a² + b² = c²

6² + 8² = c²

( 6 x 6 ) + ( 8 x 8 ) = c x c

36 cm² + 64 cm² = c²

100 cm² = c²

The area of the square is 100 cm.

c.) √c² = √100 cm²

c = 10 cm

The length of the hypotenuse is 10 cm.

QUESTION #8:

The side view of a

ramp at a grocery

store is in the shape of

a right triangle. Determine the length

of the ramp, to the nearest centimetre.

ANSWER:

a² + b² = c²

50² + 200² = c²

( 50 x 50 ) + ( 200 + 200 ) = c x c

2500 cm² + 40 000 cm² = 42500 cm²

√42500 cm² = 206 cmQUESTION # 11:

The right triangle below has a square

attached to its hypotenuse. What is the

perimeter

of the triangle? Give your

answer to the nearest tenth of a centimetre.

ANSWER:

√914 = 30.2

a² + b² = c²

17² + b² = 30.2²

b² = 30.2 ² - 17²

b² = ( 30.2 x 30.2 ) - ( 17 x 17 )

b² = 912.04 cm² - 289 cm²

b² = 623.04

√b² = √623.04

b = 24.9

The perimeter is 72.1 m.

QUESTION #14:

What are the lengths of b and c? Write your answer to the nearest tenth of a metre where

appropriate.

ANSWER:

FIRST TRIANGLE:

a² + b² = c²

3² + b² = 5²

b² = 5² - 3²

b² = ( 5 x 5 ) - ( 3 x 3 )

b² = 25 m² - 9 m²

b² = 16 m²

√b² = √16m²

b = 4 m

SECOND TRIANGLE:

a² + b² = c²

6² + 4² = c²

( 6 x 6 ) + ( 4 x 4 ) = c x c

36 m² + 16 m² = 52 m²

√c² = √52 m²

c = 7.2

HERE'S A VIDEO FOR YOU TO WATCH :)

HERE ARE SOME LINKS:

http://library.thinkquest.org/20991/geo/stri.html

http://mathforum.org/~sarah/hamilton/ham.legs.html

http://www.mathguide.com/lessons/Pythagoras.html

HOMEWORKS:

MATH TEXTBOOK. pg 104 - 105

MATH HOMEWORK BOOK pg. 30 - 31

IF I MADE A MISTAKE, PLEASE COMMENT BELOW AND CORRECT ME :)

Home Work Booklet

P.30-31
#2,4,6,8

2.
A)C=35m2
B)C=42m2

4.
A)V=12cm2
B)Z=12cm2

6.
The height of the triangle is 10.2cm2

8.I think that the triangle is not a right triangle, because the legs don't equal the hypotenuse.

a2+b2=c2
2m2+3m2=52
(2x2)+(3x3)=(5x5)
4m2+9m2=13m2
13m2 does not equal 25m2

Correct me if i am wrong on anything.

Justin Lorenzo's Math homework book Scribe Post

Our homework : math textbook pages 104 & 105, math homework book pages 30 - 31.

Math homework book pages 30 - 31 (odd numbers)

1.) Pythagorean, Length, Hypotenuse, Legs

3.)
a.) it is 41 cm
b.) it is 37 m

5.)
a.) it is 3.3 cm
b.)it is 9.7 cm

7.)
a.) it is 4.5 m
b.) it is 17 m

Tell me what you think!
Do you agree?Or disagree?

Textbook work, pages 104-105

Heeeeeeey guys! I'll be figuring out the answers to number 7, 10, 13, and 15. If I had made a mistake, please correct me! Thank you :)  Oh yeah, and if you can't see the picture that well, just click it! 

 7. What is the missing length of the leg for 

each triangle? Give your answer to the 

nearest tenth of a milimetre. 

Answer:

10.  What is the minimum distance the player 

at third base has to throw the ball to get 

the runner out at first base? Express your 

answer to the nearest tenth of a metre.

Answer:

 

13. Determine the length of the base of the 

large triangle. Express your answer to the 

nearest tenth of a milimetre. 

Answer: 

SORRY! :(  I didn't do number 15, I don't get that one.. hehe.

Pythagoras Scribe Post 5

I did numbers 6,9,12 and 15.

6.
a)
I subtract c² and a² so that i can b².
b)

I first squared the two numbers then subtract them. After that I find the square root of the difference then I got 10cm.

9.Tianna wants to construct a path along the diagonal of her yard.What length will the path be?Express your answer to the nearest tenth of a metre.

12.The hypotenuse of the triangle cuts the circle in half.What is the diameter of the circle? express your answer to the nearest tenth of a centimetre.

15.The coordinate grid shown was drawn on a centimetre grid paper. What is the length of the line segment AB. Express your answer to the nearest tenth of a centimetre.

the square root of 6.32.

Here are some links.

http://www.historyforkids.org/learn/greeks/science/math/pythagoras.htm

http://www.mathsisfun.com/pythagoras.html

Here is a video to help.


I'm not sure about my answer in no.15 but I think i'm wrong.
Leave comments and suggestions

Bennette's Square Root Scribe Post

QUESTION:
12. While shopping online, Ji Hun finds a square rug with an area of 11 m2. He needs to know if it will fit in his 4 m × 5 m bedroom.

a) Estimate the side length of the rug, to one decimal place.
b) Check your estimate with a calculator.
c) Will the rug fit? Explain.

ANSWERS:

a.) 3 x 3 = 9
4 x 4 = 16

9 is closer to 11. But in this question, they're looking for side length.
Since the side length of 9 is 3, we'll use 3 for our whole number.
3. ___

From Drop Box

Now, we just need to find out one decimal to replace the blank. To find the answer to that, count the intervals between 9 and 11.
11 - 9 = 2

The estimated answer will be, 3.2 m

b.) By using my calculator, I multiplied 3.2 by itself to check it.
3.2 x 3.2 = 10.24

To find the whole number and one decimal place, use your calculator and find the square root of 11.

From Drop Box

c.) Yes, the rug will fit because the sides of the rug is smaller than the size of his room.

Here are some links to help you:

http://www.homeschoolmath.net/teaching/square-root-algorithm.php

http://www.mathsisfun.com/square-root.html

Here are some math gaming sites for you to enjoy:

http://www.softschools.com/grades/6th_and_7th.jsp

http://www.math-play.com/Middle-School-Math-Games.html

Here are some videos for you to see:

Popout


Popout

PLEASE FEEL FREE TO GIVE SUGGESTIONS OR COMMENTS IF YOU SEE SOME ERRORS. I'LL MAKE CHANGES RIGHT AWAY :)

HOMEWORK FOR TONIGHT:

PAGES: 99 - 100

Also do " COMMUNICATE IDEAS" on page 98.

Oops Bennette blew up her scribe post

Here is what I could salvage of Bennette's scribe post.

Trish 's Square Root Scribe Post

Pages 99-1, # 17

QUESTION : Carmen wants to mount an 18 x18 cm square picture on a square board that is four times of the area of the picture.


a) What is the area of the picture?

I answered 324 cm because when you square 18 it totals to 324.

b) What is the area of the board?

For now, I know that the board is 4 times the area of the picture, and so I multiplied 324 to 4 and so the answer is 1296.

c) What are the dimensions of the board?

I answered 36 because if you will find the square root of 1296 the answer will be for sure 36.




If you're having trouble with finding the square root or having troubles with squaring a number, here our some links and videos to help you out.

http://http//www.ehow.com/how_4734274_square-square-root-number.html

http://http//www.math.com/students/calculators/source/square-root.htm

Don't forget to comment and to do our homework for today! pages 99-100, # 1-22.